C语言:扫雷小游戏

经过对C语言一段时间的学习我们可以自己进行一些小项目的编写。

​ 在扫雷游戏中,我们用了模块化设计,将不同的模块放进不同的文件里面分成head.h head.c test.c 三个部分

​ 整个代码最让我感到头疼的是find_mine函数的实现,里面有多个if else语句,并且此函数里面还有其他函数find_mine_count的调用,find_mine_count函数还有一种实现方法是将mine[x][y]周围的八个元素相加减去8*’0’,返回结果。

如下:

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int find_mine_count(char mine[ROWS][COLS], int x, int y)
{
return mine[x + 1][y + 1] +
mine[x][y + 1] +
mine[x - 1][y + 1] +
mine[x - 1][y] +
mine[x - 1][y - 1] +
mine[x][y - 1] +
mine[x + 1][y - 1] +
mine[x + 1][y] - 8 * '0';

}

话不多说上代码!

head.c

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#include "head.h"
void menu(void)
{
printf("*************************************\n");
printf("************* 0. Exit **************\n");
printf("*************************************\n");
printf("************* 1. Play **************\n");
printf("*************************************\n");
}

void init_board(char board[ROWS][COLS], int rows, int cols, char set)
{
for (int i = 0; i <= rows; i++)
{
for (int j = 0; j <= cols; j++)
{
board[i][j] = set;
}
}
}

void display_board(char board[ROWS][COLS], int row, int col)
{
int i = 0;
int j = 0;
printf("-----欢 迎 来 到 扫 雷 游 戏------\n");
for (i = 0; i <= col; i++)
{
printf("%2d ", i);
}
printf("\n");
for (i = 1; i <= row; i++)
{
printf("%2d ", i);
for (j = 1; j <= col; j++)
{
printf("%2c ", board[i][j]);
}
printf("\n");
}
}

void set_mine(char board[ROWS][COLS], int row, int col)
{

int count=mid_count;
while (count)
{
int x = rand() % row + 1;
int y = rand() % col + 1;

if(board[x][y]=='0')
{
board[x][y] = '1';
count--;
}
}
}

int find_mine_count(char mine[ROWS][COLS], int x, int y)
{
int count = 0;
int i = 0;
for (i = x - 1; i <= x + 1; i++)
{
int j = 0;
for (j = x - 1; j <= x + 1; j++)
{
count += (mine[i][j]-'0');
}
}
return count;
}

void find_mine(char mine[ROWS][COLS],char show[ROWS][COLS],int row, int col)
{
int win = 0;
int x = 0;
int y = 0;
while (win < row * col - easy_count)
{
printf("\n请输入要排除的坐标:");

scanf("%d %d", &x, &y);

if (x >= 1 && x <= row && y >= 1 && y <= col)
{
if (show[x][y] == '*')
{
if (mine[x][y] == '1')
{
printf("\n恭喜你被炸死了!\n");
display_board(mine, ROW, COL);
}
else
{
int mine_count = find_mine_count(mine, x, y);
show[x][y] = mine_count+'0';
display_board(show, ROW, COL);
win++;
}
}
else
{
printf("该坐标已被排查,请重新输入坐标!\n");
}
}
else
{
printf("坐标非法,重新输入!\n");
}
}
if (win == row * col - easy_count)
{
printf("\n很遗憾你把雷全部排查完了,游戏结束!\n");
}
}

head.h

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#pragma once
#define _CRT_SECURE_NO_WARNINGS

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

#define ROW 20
#define COL 20

#define ROWS ROW+2
#define COLS COL+2

#define easy_count 10
#define mid_count 25
#define max_count 50
//菜单
void menu(void);

//初始化棋盘
void init_board(char board[ROWS][COLS], int rows, int cols, char set);

//打印棋盘
void display_board(char board[ROWS][COLS], int row, int col);

//布置雷
void set_mine(char board[ROWS][COLS], int row, int col);

//排除雷
void find_mine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

test.c

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#include "head.h"

void test()
{
char show[ROWS][COLS] = { 0 };
char mine[ROWS][COLS] = { 0 };

init_board(show, ROWS, COLS, '*');
init_board(mine, ROWS, COLS, '0');

//display_board(show, ROW, COL);
//display_board(mine, ROW, COL);

set_mine(mine,ROW,COL);
display_board(show, ROW, COL);
//display_board(mine, ROW, COL);

find_mine(mine, show, ROW, COL);

}

int main()
{
srand((unsigned int)time(NULL));
int input = 0;
do
{
menu();
printf("请输入:\n");
scanf("%d", &input);
switch (input)
{
case 1:
test();
continue;
case 0:
printf("游戏结束\n");
break;
default:
printf("输入有误,请重新输入!\n");
break;
}
} while (input);
return 0;

这个版本的扫雷游戏只是最简版本,后续还可以添加其他有趣功能:

img